• imPastaSyndrome@lemm.ee
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    5 months ago

    The exact dimensions of an 80-pound stainless steel block would depend on its specific shape. However, we can estimate its size based on the density of stainless steel, which is around 490 lbs per cubic foot (lb/ft³). To find the volume of the block, we can divide its weight (80 lbs) by its density (490 lb/ft³):

    Volume = Weight / Density. Volume = 80 lbs / 490 lb/ft³. Volume ≈ 0.16 cubic feet (ft³).

    Since we don’t have a specific shape for the block, let’s assume it’s a cube for simplicity. To calculate the side length of a cube with a volume of 0.16 ft³, we can take the cube root of the volume:

    Side length = ³√Volume.
    Side length = ³√0.16 ft³.
    Side length ≈ 0.54 ft (or about 6.5 inches).

    Therefore, an 80-pound stainless steel block shaped like a cube would have sides measuring around 6.5 inches each.

      • imPastaSyndrome@lemm.ee
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        5 months ago

        Well fuck you.

        Edit: Sorry. That makes sense, I just was thinking about that tiny heavy cube you can buy that’s like the densest cube of metal and I wanted to get the math done because it was ENTIRELY too big in the photo in my estimation, and why would it be hollow? To take up more space sure but it would dent and be so much harder to produce but I GUESS I get it. UGH

        Didn’t feel like doing the math for a hollow one myself so I asked bing to do it for me assuming it was about 10 inches in diameter (that’s what I guessed from the photo because it looked to be approximately as wide as one burner(?) it’d be 72% hollow