• logicbomb@lemmy.world
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    11 months ago

    Also, any number whose digits sum to a multiple of 3 is divisible by 3. For 51, 5+1=6, and 6 is a multiple of 3, so 51 can be cleanly divided by 3.

      • logicbomb@lemmy.world
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        11 months ago

        I only know rules for 2 (even number), 3 (digits sum to 3), 4 (last two digits are divisible by 4), 5 (ends in 5 or 0), 6 (if it satisfies the rules for both 3 and 2), 9 (digits sum to 9), and 10 (ends in 0).

        I don’t know of one for 7, 8 or 13. 11 has a limited goofy one that involves seeing if the outer digits sum to the inner digits. 12 is divisible by both 3 and 4, so like 6, it has to satisfy both of those rules.

    • vortic@lemmy.world
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      11 months ago

      I’d forgotten this trick. It works for large numbers too.

      122,300,223÷3 = 40,766, 741

      1+2+2+3+2+2+3 = 15