Day 14: Restroom Redoubt

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FAQ

  • sjmulder@lemmy.sdf.org
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    8 days ago

    C

    Solved part 1 without a grid, looked at part 2, almost spit out my coffee. Didn’t see that coming!

    I used my visualisation mini-library to generate video with ffmpeg, stepped through it a bit, then thought better of it - this is a programming puzzle after all!

    So I wrote a heuristic to find frames low on entropy (specifically: having many robots in the same line of column), where each record-breaking frame number was printed. That pointed right at the correct frame!

    It was pretty slow though (.2 secs or such) because it required marking spots on a grid. I noticed the Christmas tree was neatly tucked into a corner, concluded that wasn’t an accident, and rewrote the heuristic to check for a high concentration in a single quadrant. Reverted this because the tree-in-quadrant assumption proved incorrect for other inputs. Would’ve been cool though!

    Code
    #include "common.h"
    
    #define SAMPLE 0
    #define GW (SAMPLE ? 11 : 101)
    #define GH (SAMPLE ?  7 : 103)
    #define NR 501
    
    int
    main(int argc, char **argv)
    {
    	static char g[GH][GW];
    	static int px[NR],py[NR], vx[NR],vy[NR];
    
    	int p1=0, n=0, sec, i, x,y, q[4]={}, run;
    
    	if (argc > 1)
    		DISCARD(freopen(argv[1], "r", stdin));
    
    	for (; scanf(" p=%d,%d v=%d,%d", px+n,py+n, vx+n,vy+n)==4; n++)
    		assert(n+1 < NR);
    
    	for (sec=1; !SAMPLE || sec <= 100; sec++) {
    		memset(g, 0, sizeof(g));
    		memset(q, 0, sizeof(q));
    
    		for (i=0; i<n; i++) {
    			px[i] = (px[i] + vx[i] + GW) % GW;
    			py[i] = (py[i] + vy[i] + GH) % GH;
    
    			g[py[i]][px[i]] = 1;
    
    			if (sec == 100) {
    				if (px[i] < GW/2) {
    					if (py[i] < GH/2) q[0]++; else
    					if (py[i] > GH/2) q[1]++;
    				} else if (px[i] > GW/2) {
    					if (py[i] < GH/2) q[2]++; else
    					if (py[i] > GH/2) q[3]++;
    				}
    			}
    		}
    
    		if (sec == 100)
    			p1 = q[0]*q[1]*q[2]*q[3];
    
    		for (y=0; y<GH; y++)
    		for (x=0, run=0; x<GW; x++)
    			if (!g[y][x])
    				run = 0;
    			else if (++run >= 10)
    				goto found_p2;
    	}
    
    found_p2:
    	printf("14: %d %d\n", p1, sec);
    	return 0;
    }
    

    https://github.com/sjmulder/aoc/blob/master/2024/c/day14.c