Day 12: Garden Groups

Megathread guidelines

  • Keep top level comments as only solutions, if you want to say something other than a solution put it in a new post. (replies to comments can be whatever)
  • You can send code in code blocks by using three backticks, the code, and then three backticks or use something such as https://topaz.github.io/paste/ if you prefer sending it through a URL

FAQ

  • mykl@lemmy.world
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    11 days ago

    Dart

    Filling to find regions was easy. Counting areas was easy. Counting fences was okay. Counting sides caused me a lot of frustration as I tried and rejected a number of approaches, eventually arriving at a reasonably simple corner-counting approach. None of this was helped by all the examples lacking at least two important layouts, causing today to be the first day that I ran out of hints for wrong answers :-(.

    (corners is where the magic happens)

    70 or so lines, half a second to run, so that's fine for today.
    import 'dart:math';
    import 'package:collection/collection.dart';
    import 'package:more/more.dart';
    
    const List<Point> n4 = [Point(0, 1), Point(0, -1), Point(1, 0), Point(-1, 0)];
    List<Point> n8 = n4 + [Point(1, 1), Point(1, -1), Point(-1, 1), Point(-1, -1)];
    const List<Point> c4 = [Point(0, 0), Point(0, 1), Point(1, 0), Point(1, 1)];
    
    (Map<Point, String>, Map<Point, List<Point>>) parse(ls) {
      var nodes = {
        for (var y in 0.to(ls.length))
          for (var x in 0.to(ls.first.length)) Point<num>(x, y): ls[y][x] as String
      };
      var nexts = Map.fromEntries(nodes.keys.map((n) => MapEntry(
          n,
          n4
              .map((d) => n + d)
              .where((d) => (nodes[d] ?? '') == nodes[n]!)
              .toList())));
      return (nodes, nexts);
    }
    
    (int, Set<Point>) survey(
        Point here, String target, Map<Point<num>, List<Point>> nexts,
        [Set sofar = const {}]) {
      seen.add(here);
      var fences = 4 - nexts[here]!.length;
      var area = {here};
      for (var f in nexts[here]!.where((e) => !seen.contains(e))) {
        var (fs, a) = survey(f, target, nexts, sofar.toSet()..add(f));
        fences += fs;
        area.addAll(a);
      }
      return (fences, area);
    }
    
    late Set<Point> seen;
    List<(int, Set<Point<num>>)> costs(List<String> lines) {
      seen = {};
      var ret = <(int, Set<Point<num>>)>[];
      var (nodes, nexts) = parse(lines);
      var toVisit = nodes.keys.toSet();
      while (toVisit.isNotEmpty) {
        var here = toVisit.first;
        toVisit.remove(here);
        ret.add(survey(here, nodes[here]!, nexts));
        toVisit.removeAll(seen);
      }
      return ret;
    }
    
    Function eq = const ListEquality().equals;
    int corners(Set<Point> points) {
      var border = points.map((e) => n8.map((n) => n + e)).flattenedToSet
        ..addAll(points);
      // A corner is where a 2x2 grid contains one/three in-shape points, or
      // two diagonally-opposite cells
      var corners = 0;
      for (var cell in border) {
        var count = c4.map((e) => points.contains(e + cell)).toList();
        if (count.count((e) => e) % 2 == 1) {
          corners += 1;
        } else {
          if (eq(count, [true, false, false, true]) ||
              eq(count, [false, true, true, false])) {
            corners += 2;
          }
        }
      }
      return corners;
    }
    
    part1(lines) => costs(lines).map((e) => e.first * e.last.length).sum;
    part2(lines) => costs(lines).map((e) => corners(e.last) * e.last.length).sum;