I don’t think I would call this functional. Python is decidedly not at all functional - there’s no way to declare arbitrary functions inline, no chaining of map/filter etc.
But the static types are definitely welcome. I didn’t know about the type keyword. Apparently it makes it support forward references.
You’re still limited by lambda expressions though. And in general the language is still statement based, not expression based. You can’t do a = if foo then x else y type things (except for the one-off and backwards x if foo else y; they were so close!).
It’s not. In functional languages there’s no special case like this. All if-elses are expressions. It’s far superior. For example how do you do this with Python’s if-else expression?
let x = if foo {
let y = bar();
baz();
y
} else {
z
}
foo isn’t a function, it’s a bool. But in any case, as you can see the answer is “with terrible hacks”. Python is not a functional language. It is imperative.
I don’t think I would call this functional. Python is decidedly not at all functional - there’s no way to declare arbitrary functions inline, no chaining of map/filter etc.
But the static types are definitely welcome. I didn’t know about the
typekeyword. Apparently it makes it support forward references.like everything in python, to achieve functional you must first
import functional(not even a joke)
You’re still limited by lambda expressions though. And in general the language is still statement based, not expression based. You can’t do
a = if foo then x else ytype things (except for the one-off and backwardsx if foo else y; they were so close!).“a = x if foo else y” is a perfectly cromulent statement!
It’s not. In functional languages there’s no special case like this. All if-elses are expressions. It’s far superior. For example how do you do this with Python’s if-else expression?
let x = if foo { let y = bar(); baz(); y } else { z }x = foo(y:=bar(), baz(), y) or zshould work assuming foo bar and baz are functions being called?if this is setting y to the effect of bar() + running baz after, then:
x = [bar(), baz()][0] or zmight work
and if you need y to be defined for later use:
x = [(y:=bar()), baz()][0] or zbut thats from memory, not sure if that will even run as written.
if I get to a real computer I'll try that with an actual if statement instead of a bastardized ternary.fooisn’t a function, it’s a bool. But in any case, as you can see the answer is “with terrible hacks”. Python is not a functional language. It is imperative.Yeah, never said it was, just that if you really want to emulate that style you mostly can.