Even cooler, at 75 digits you can calculate the circumference of your mom
Diameter of a hydrogen atom is all well and good, but how many digits of pi will we need to be accurate to a Planck Length?
Honestly probably not that many more. My guess since I’m too lazy to do the math is less than 100.
The diameter of a hydrogen atom is over 10,000,000,000,000,000,000,000,000 plank lengths.
So based on this post I have no idea.
Well that’s only 26 more digits, so we’re probably good at 100 digits of pi. [citation needed]
log_10(size of observable universe / planck length) = 61.74… so like 63 digits of precision for everything are enough
There’s a 9 repeating 6 times in there which I’d think is a pretty rare occurrence in pi. I wonder what the longest occurrence of a repeating digit is.
Pi is infinite so every combination/string of numbers is in there, if we calculated enough you could find a billion 2s next to each other
You can look through the first trillion here
https://archive.org/details/pi_dec_1t
Though it’s a bunch of downloading
Not necessarily. It could just become a series of 1’s repeating forever. Nothing would require it to contain all strings of numbers.
The point of pi is that it’s non-repeating
Take a look at 0.101001000100001… This number is also non-repeating, but obviously doesn’t contain all numbers with finite digits.
The property you’re looking for is called to be a normal number. Pi is assumed to be one, but it hasn’t yet been proven.
However, in a sense this is an unremarkable property as almost all real numbers are normal. :)
