Day 9: Disk Fragmenter
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FAQ
- What is this?: Here is a post with a large amount of details: https://programming.dev/post/6637268
- Where do I participate?: https://adventofcode.com/
- Is there a leaderboard for the community?: We have a programming.dev leaderboard with the info on how to join in this post: https://programming.dev/post/6631465
Haskell
Not a lot of time to come up with a pretty solution today; sorry.
Ugly first solution
import Data.List import Data.Maybe import Data.Sequence (Seq) import Data.Sequence qualified as Seq readInput :: String -> Seq (Maybe Int, Int) readInput = Seq.fromList . zip (intersperse Nothing $ map Just [0 ..]) . (map (read . singleton) . head . lines) expand :: Seq (Maybe Int, Int) -> [Maybe Int] expand = concatMap (uncurry $ flip replicate) compact :: Seq (Maybe Int, Int) -> Seq (Maybe Int, Int) compact chunks = case Seq.spanr (isNothing . fst) chunks of (suffix, Seq.Empty) -> suffix (suffix, chunks' Seq.:|> file@(_, fileSize)) -> case Seq.breakl (\(id, size) -> isNothing id && size >= fileSize) chunks' of (_, Seq.Empty) -> compact chunks' Seq.>< file Seq.<| suffix (prefix, (Nothing, gapSize) Seq.:<| chunks'') -> compact $ prefix Seq.>< file Seq.<| (Nothing, gapSize - fileSize) Seq.<| chunks'' Seq.>< (Nothing, fileSize) Seq.<| suffix part1, part2 :: Seq (Maybe Int, Int) -> Int part1 input = let blocks = dropWhileEnd isNothing $ expand input files = catMaybes blocks space = length blocks - length files compacted = take (length files) $ fill blocks (reverse files) in sum $ zipWith (*) [0 ..] compacted where fill (Nothing : xs) (y : ys) = y : fill xs ys fill (Just x : xs) ys = x : fill xs ys part2 = sum . zipWith (\i id -> maybe 0 (* i) id) [0 ..] . expand . compact main = do input <- readInput <$> readFile "input09" print $ part1 input print $ part2 input
Second attempt! I like this one much better.
Edit: down to 0.040 secs now!
import Control.Arrow import Data.Either import Data.List import Data.Map (Map) import Data.Map qualified as Map type Layout = ([(Int, (Int, Int))], Map Int Int) readInput :: String -> Layout readInput = map (read . singleton) . head . lines >>> (scanl' (+) 0 >>= zip) -- list of (pos, len) >>> zipWith ($) (intersperse Right [Left . (id,) | id <- [0 ..]]) >>> partitionEithers >>> filter ((> 0) . snd . snd) *** Map.filter (> 0) . Map.fromAscList checksum :: Layout -> Int checksum = sum . map (\(id, (pos, len)) -> id * len * (2 * pos + len - 1) `div` 2) . fst compact :: (Int -> Int -> Bool) -> Layout -> Layout compact select (files, spaces) = foldr moveFile ([], spaces) files where moveFile file@(fileId, (filePos, fileLen)) (files, spaces) = let candidates = Map.assocs $ fst . Map.split filePos $ spaces in case find (select fileLen . snd) candidates of Just (spacePos, spaceLen) -> let spaces' = Map.delete spacePos spaces in if spaceLen >= fileLen then ( (fileId, (spacePos, fileLen)) : files, if spaceLen == fileLen then spaces' else Map.insert (spacePos + fileLen) (spaceLen - fileLen) spaces' ) else moveFile (fileId, (filePos + spaceLen, fileLen - spaceLen)) ((fileId, (spacePos, spaceLen)) : files, spaces') Nothing -> (file : files, spaces) main = do input <- readInput <$> readFile "input09" mapM_ (print . checksum . ($ input) . compact) [const $ const True, (<=)]
It will always be a wonder to me how you manage to do so much in so few lines, even your naive solution only takes a few seconds to run. 🤯
Aww, thank you <3
It’s just practice, I guess? (The maths degree probably doesn’t hurt either)
Maths degree at least explains the choice of language